Optimal. Leaf size=369 \[ \frac{8 a^{11/4} \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} \left (77 \sqrt{a} B+195 A \sqrt{c}\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{3003 c^{3/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{8 a^2 \sqrt{e x} \sqrt{a+c x^2} (195 A+77 B x)}{3003 e}-\frac{16 a^{13/4} B \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{39 c^{3/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{16 a^3 B x \sqrt{a+c x^2}}{39 \sqrt{c} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{20 a \sqrt{e x} \left (a+c x^2\right )^{3/2} (117 A+77 B x)}{9009 e}+\frac{2 \sqrt{e x} \left (a+c x^2\right )^{5/2} (13 A+11 B x)}{143 e} \]
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Rubi [A] time = 0.414119, antiderivative size = 369, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {815, 842, 840, 1198, 220, 1196} \[ \frac{8 a^{11/4} \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} \left (77 \sqrt{a} B+195 A \sqrt{c}\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{3003 c^{3/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{8 a^2 \sqrt{e x} \sqrt{a+c x^2} (195 A+77 B x)}{3003 e}-\frac{16 a^{13/4} B \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{39 c^{3/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{16 a^3 B x \sqrt{a+c x^2}}{39 \sqrt{c} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{20 a \sqrt{e x} \left (a+c x^2\right )^{3/2} (117 A+77 B x)}{9009 e}+\frac{2 \sqrt{e x} \left (a+c x^2\right )^{5/2} (13 A+11 B x)}{143 e} \]
Antiderivative was successfully verified.
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Rule 815
Rule 842
Rule 840
Rule 1198
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{(A+B x) \left (a+c x^2\right )^{5/2}}{\sqrt{e x}} \, dx &=\frac{2 \sqrt{e x} (13 A+11 B x) \left (a+c x^2\right )^{5/2}}{143 e}+\frac{20 \int \frac{\left (\frac{13}{2} a A c e^2+\frac{11}{2} a B c e^2 x\right ) \left (a+c x^2\right )^{3/2}}{\sqrt{e x}} \, dx}{143 c e^2}\\ &=\frac{20 a \sqrt{e x} (117 A+77 B x) \left (a+c x^2\right )^{3/2}}{9009 e}+\frac{2 \sqrt{e x} (13 A+11 B x) \left (a+c x^2\right )^{5/2}}{143 e}+\frac{80 \int \frac{\left (\frac{117}{4} a^2 A c^2 e^4+\frac{77}{4} a^2 B c^2 e^4 x\right ) \sqrt{a+c x^2}}{\sqrt{e x}} \, dx}{3003 c^2 e^4}\\ &=\frac{8 a^2 \sqrt{e x} (195 A+77 B x) \sqrt{a+c x^2}}{3003 e}+\frac{20 a \sqrt{e x} (117 A+77 B x) \left (a+c x^2\right )^{3/2}}{9009 e}+\frac{2 \sqrt{e x} (13 A+11 B x) \left (a+c x^2\right )^{5/2}}{143 e}+\frac{64 \int \frac{\frac{585}{8} a^3 A c^3 e^6+\frac{231}{8} a^3 B c^3 e^6 x}{\sqrt{e x} \sqrt{a+c x^2}} \, dx}{9009 c^3 e^6}\\ &=\frac{8 a^2 \sqrt{e x} (195 A+77 B x) \sqrt{a+c x^2}}{3003 e}+\frac{20 a \sqrt{e x} (117 A+77 B x) \left (a+c x^2\right )^{3/2}}{9009 e}+\frac{2 \sqrt{e x} (13 A+11 B x) \left (a+c x^2\right )^{5/2}}{143 e}+\frac{\left (64 \sqrt{x}\right ) \int \frac{\frac{585}{8} a^3 A c^3 e^6+\frac{231}{8} a^3 B c^3 e^6 x}{\sqrt{x} \sqrt{a+c x^2}} \, dx}{9009 c^3 e^6 \sqrt{e x}}\\ &=\frac{8 a^2 \sqrt{e x} (195 A+77 B x) \sqrt{a+c x^2}}{3003 e}+\frac{20 a \sqrt{e x} (117 A+77 B x) \left (a+c x^2\right )^{3/2}}{9009 e}+\frac{2 \sqrt{e x} (13 A+11 B x) \left (a+c x^2\right )^{5/2}}{143 e}+\frac{\left (128 \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{\frac{585}{8} a^3 A c^3 e^6+\frac{231}{8} a^3 B c^3 e^6 x^2}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{9009 c^3 e^6 \sqrt{e x}}\\ &=\frac{8 a^2 \sqrt{e x} (195 A+77 B x) \sqrt{a+c x^2}}{3003 e}+\frac{20 a \sqrt{e x} (117 A+77 B x) \left (a+c x^2\right )^{3/2}}{9009 e}+\frac{2 \sqrt{e x} (13 A+11 B x) \left (a+c x^2\right )^{5/2}}{143 e}-\frac{\left (16 a^{7/2} B \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{c} x^2}{\sqrt{a}}}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{39 \sqrt{c} \sqrt{e x}}+\frac{\left (16 a^3 \left (77 \sqrt{a} B+195 A \sqrt{c}\right ) \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{3003 \sqrt{c} \sqrt{e x}}\\ &=\frac{8 a^2 \sqrt{e x} (195 A+77 B x) \sqrt{a+c x^2}}{3003 e}+\frac{16 a^3 B x \sqrt{a+c x^2}}{39 \sqrt{c} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{20 a \sqrt{e x} (117 A+77 B x) \left (a+c x^2\right )^{3/2}}{9009 e}+\frac{2 \sqrt{e x} (13 A+11 B x) \left (a+c x^2\right )^{5/2}}{143 e}-\frac{16 a^{13/4} B \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{39 c^{3/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{8 a^{11/4} \left (77 \sqrt{a} B+195 A \sqrt{c}\right ) \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{3003 c^{3/4} \sqrt{e x} \sqrt{a+c x^2}}\\ \end{align*}
Mathematica [C] time = 0.0289217, size = 85, normalized size = 0.23 \[ \frac{2 a^2 x \sqrt{a+c x^2} \left (3 A \, _2F_1\left (-\frac{5}{2},\frac{1}{4};\frac{5}{4};-\frac{c x^2}{a}\right )+B x \, _2F_1\left (-\frac{5}{2},\frac{3}{4};\frac{7}{4};-\frac{c x^2}{a}\right )\right )}{3 \sqrt{e x} \sqrt{\frac{c x^2}{a}+1}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.014, size = 362, normalized size = 1. \begin{align*}{\frac{2}{9009\,c} \left ( 693\,B{c}^{4}{x}^{8}+819\,A{c}^{4}{x}^{7}+2849\,aB{c}^{3}{x}^{6}+2340\,A\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ) \sqrt{2}\sqrt{-ac}{a}^{3}+3627\,aA{c}^{3}{x}^{5}+1848\,B\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticE} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ) \sqrt{2}{a}^{4}-924\,B\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ) \sqrt{2}{a}^{4}+4543\,{a}^{2}B{c}^{2}{x}^{4}+7137\,{a}^{2}A{c}^{2}{x}^{3}+2387\,{a}^{3}Bc{x}^{2}+4329\,{a}^{3}Acx \right ){\frac{1}{\sqrt{c{x}^{2}+a}}}{\frac{1}{\sqrt{ex}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{2} + a\right )}^{\frac{5}{2}}{\left (B x + A\right )}}{\sqrt{e x}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B c^{2} x^{5} + A c^{2} x^{4} + 2 \, B a c x^{3} + 2 \, A a c x^{2} + B a^{2} x + A a^{2}\right )} \sqrt{c x^{2} + a} \sqrt{e x}}{e x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 38.4862, size = 301, normalized size = 0.82 \begin{align*} \frac{A a^{\frac{5}{2}} \sqrt{x} \Gamma \left (\frac{1}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{1}{4} \\ \frac{5}{4} \end{matrix}\middle |{\frac{c x^{2} e^{i \pi }}{a}} \right )}}{2 \sqrt{e} \Gamma \left (\frac{5}{4}\right )} + \frac{A a^{\frac{3}{2}} c x^{\frac{5}{2}} \Gamma \left (\frac{5}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{5}{4} \\ \frac{9}{4} \end{matrix}\middle |{\frac{c x^{2} e^{i \pi }}{a}} \right )}}{\sqrt{e} \Gamma \left (\frac{9}{4}\right )} + \frac{A \sqrt{a} c^{2} x^{\frac{9}{2}} \Gamma \left (\frac{9}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{9}{4} \\ \frac{13}{4} \end{matrix}\middle |{\frac{c x^{2} e^{i \pi }}{a}} \right )}}{2 \sqrt{e} \Gamma \left (\frac{13}{4}\right )} + \frac{B a^{\frac{5}{2}} x^{\frac{3}{2}} \Gamma \left (\frac{3}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{3}{4} \\ \frac{7}{4} \end{matrix}\middle |{\frac{c x^{2} e^{i \pi }}{a}} \right )}}{2 \sqrt{e} \Gamma \left (\frac{7}{4}\right )} + \frac{B a^{\frac{3}{2}} c x^{\frac{7}{2}} \Gamma \left (\frac{7}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{7}{4} \\ \frac{11}{4} \end{matrix}\middle |{\frac{c x^{2} e^{i \pi }}{a}} \right )}}{\sqrt{e} \Gamma \left (\frac{11}{4}\right )} + \frac{B \sqrt{a} c^{2} x^{\frac{11}{2}} \Gamma \left (\frac{11}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{11}{4} \\ \frac{15}{4} \end{matrix}\middle |{\frac{c x^{2} e^{i \pi }}{a}} \right )}}{2 \sqrt{e} \Gamma \left (\frac{15}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{2} + a\right )}^{\frac{5}{2}}{\left (B x + A\right )}}{\sqrt{e x}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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